最終更新日:2022/12/24

This case suggests that the alternation of a polyhedron should be bounded by actual vertex figures and alternated faces. The case of the cube is in agreement with this notion, since the alternated square is nothing.

音声機能が動作しない場合はこちらをご確認ください
編集履歴(0)

Sentence quizzes to help you learn to read

編集履歴(0)

ログイン / 新規登録

 

アプリをダウンロード!
DiQt

DiQt(ディクト)

無料

★★★★★★★★★★