最終更新日:2025/11/30
The mathematician showed that the function mapped the set surjectively onto its codomain, so every element had at least one preimage.
正解を見る
The mathematician showed that the function mapped the set surjectively onto its codomain, so every element had at least one preimage.
音声機能が動作しない場合はこちらをご確認ください
編集履歴(0)