Inexpressibly tired of this anxious intricate search I threw myself down on the soft moss to rest for a while, but the fatigue conquered the fears of the lonely forest, and I cannot now tell how long I dozed.

Hey, you, wharra you lookin' at?

We have already pointed out that a profinite group G of an infinite rank m is free of rank m if (and only if) G is projective and every finite split embedding problem for G with a nontrivial kernel has m solutions (Proposition 9.4.7). Dropping the condition on G to be projective leads to the notion of a quasi-free profinite group (Section 10.6).

He suggested a Rose Ballet in which he would use the G. V. Follies chorus girls, chiefly the ponies and mediums.