Last Updated：2025/11/21
Sentence
定理を証明するために、彼女はまず異なる固有値に対応する固有ベクトルが非自明な線形結合でゼロにならない、つまり線形独立であることを示した。
Quizzes for review
To prove the theorem, she first showed that the eigenvectors corresponding to distinct eigenvalues are linearly independent.
See correct answer
To prove the theorem, she first showed that the eigenvectors corresponding to distinct eigenvalues are linearly independent.
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Related words
linearly independent
Adjective
not-comparable
Japanese Meaning
線形代数における "linearly independent" は、あるベクトルや環の元の集合において、全ての非自明な（すべての係数が0でない）線形結合が0にならない、つまり0となるためには各係数が全て0でなければならないという性質を指します。
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