Last Updated：2025/12/31
Sentence
We
also
prove
that
M
is
without
weights
m,…,n
(i.e.,
a
decomposition
of
M
avoiding
these
weights
exists)
if
and
only
if
the
corresponding
condition
is
fulfilled
for
its
weight
complex
t(M).
Moreover,
we
improve
significantly
the
conservativity
properties
of
the
functor
t
(that
were
established
in
a
preceding
paper).
Quizzes for review
We also prove that M is without weights m,…,n (i.e., a decomposition of M avoiding these weights exists) if and only if the corresponding condition is fulfilled for its weight complex t(M). Moreover, we improve significantly the conservativity properties of the functor t (that were established in a preceding paper).
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English - English
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