Last Updated：2025/12/31
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If f(x)=bˣ then F(x)=bˣ/(b-1)+C is the general antidifference since F(x+1)-F(x) = [bˣ⁺¹/(b-1)+C] - [bˣ/(b-1)+C] = (bˣ⁺¹-bˣ)/(b-1) = bˣ = f(x).
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