Last Updated：2025/12/30
Sentence
If
synchronization
is
always
performed
in
least-first
order
with
respect
to
object
tags,
then
situations
can
never
arise
in
which
one
thread
has
the
synchronization
lock
for
x
while
waiting
for
y
and
another
has
the
lock
for
y
while
waiting
for
x.
Instead,
they
will
both
obtain
the
locks
in
the
same
order,
thus
avoiding
this
form
of
deadlock.
Quizzes for review
If synchronization is always performed in least-first order with respect to object tags, then situations can never arise in which one thread has the synchronization lock for x while waiting for y and another has the lock for y while waiting for x. Instead, they will both obtain the locks in the same order, thus avoiding this form of deadlock.
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