Last Updated:2025/11/24

To prove the theorem, we constructed a directed path from vertex u to vertex v that avoids all forbidden edges.

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To prove the theorem, we constructed a directed path from vertex u to vertex v that avoids all forbidden edges.

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定理を証明するために、私たちは頂点uから頂点vへの有向パスを構成し、すべての禁止された辺を回避しました。

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