Last Updated：2025/12/01

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(mathematics) That has a zero Jacquet functor for every proper parabolic subgroup

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supercuspidal

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Source Word

supercuspidal

Adjective

not-comparable

(mathematics) That has a zero Jacquet functor for every proper parabolic subgroup

Japanese Meaning

数学において、すべての適切な副交代群に対してヤック関手がゼロとなる対象、すなわち超尖性（supercuspidal）の性質を持つものである。

What is this buttons?

The theorem classifies supercuspidal representations as those whose Jacquet functor vanishes for every proper parabolic subgroup.

Google Translation / DeepL Translation

この定理は、任意の真部分パラボリック部分群に対してJacquet 関手が零となる表示を分類する。

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(mathematics) That has a zero Jacquet functor for every proper parabolic subgroup

A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).

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supercuspidal

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supercuspidal

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